Презентация к уроку математики "Закрепление вычислительных навыков в пределах 10."Цветик-семицветик" 1 класс

Сазнова Т.Е. учитель начальных классов МОУ СОШ №222 г.Заречный Пензенская обл.

2–2= 2–1= 4–2= 4–1= 1+1= 3+1= 1+2= 3–2= 3–1= 0+2= 4–3= 2+2= 3+1–2= 4–4+3= 1+2+1= 2–0= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

1+1= 3–1= 2–1= 4–2= 4–1= 3+1= 1+2= 3–2= 4–3= 2+2= 3+1–2= 4–4+3= 1+2+1= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

3+1= 3–1= 4–2= 4–1= 1+2= 3–2= 4–3= 2+2= 3+1–2= 4–4+3= 1+2+1= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

4–1= 3+1= 3–1= 1+2= 3–2= 4–3= 3+1–2= 4–4+3= 1+2+1= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

1+2= 3–2= 3–1= 3+1–2= 4–4+3= 1+2+1= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

3+1–2= 4–4+3= 1+2+1= 3 – 2 + 3 = 4 – 2 + 1 = 0 + 4 – 3 = 4 – (2 + 1)= 3 + (4 – 1) = 2– (4 – 3)= 4 – (4 – 2) =

4 6 0 5 1 3 2 4 – (2 + 1)= 3 + (2 – 1) = 4– (4 – 3)= 4 – (4 – 2) =

6 0 4 5 1 3 2 3 + (2 – 1) = 4– (4 – 3)= 4 – (4 – 2) =

6 0 4 5 1 3 2 4– (4 – 3)= 4 – (4 – 2) =

6 0 4 5 1 3 2 4 – (4 – 2) =

2+3 6–1 4+1 6–4 5 Составьте –2 6 – обратные 5 5 – 1 примеры 6–2 5–3 5+1 5–4 4+2 5+0 6–3 6–6 10 + 1 3+3 6–0 11 – 1 6+0 11 – 10 5–0 5–5

7–0 4+3 6+1 3+3 5–2 7–7 7–2 7–6 0+7 6–4 Найдите «лишние примеры». 2+5 7–3 4–2 7–5 7–4 7–1

4+4= 8–7= 0 8–5= 8+0= 7 1+7= 8–4= 6 6+2= 8–3= 5+3= 4 8–6= 1 8–0= 3 3+4= 8–8= 5 8–1= 8 8–2= 2

0 9–4 5 93 –6 3+6 9 9–9 7 9-7 2 99 +0 5+4 9 9–2 4 98 –1 19 +8 9–5 9 9–0 1 96 –3 7+2 9 9–8

10 – 8=10 4 + 6= 8 5 + 5 = 6 10 – 3= 5 0 + 10= 2 10 – 7= 4 10–10=10 1 + 9 = 7 7 + 3 = 1 10 – 2=10 10– 4= 10 10 – 5= 9 10 – 9=10 10 – 6=3 8 + 2 = 0 10 – 1= 10

3–2 9–5 10–6+3= 9–(7–2)= 7 – 5Решите 6–1 3+7–6= 10-(6+3)= круговые 5 +примеры 5 9–3 8- 4+5= 4+(7–5 )= 1+8 8–5 5+2+3= 3+(2+5)= 4+4 2+7 9–7+6= 8–(10–4)= 10 – 3 10 8 9 4 7

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